OCP Question 58, Explanation


public class B implements A {
    public String toString() {
        return "B ";
    public static void main(String[] args) {
        C myC = new C();
        B myB = myC;
        A myA = myB;
        System.out.print((C) myB);
class C extends B {
    public String toString() {
        return "C ";
interface A {
    public String toString();

What is the result?

A. B B B
B. B C B
C. C C B
D. C C C
E. The code throws a ClassCastException


The correct answer is D.


This Problem is so simple we don’t even need to draw pictures or apply the castype-related rule (ref.to Nailing 1Z0-809, page 312, if you are unsure what castype stands for). It is sufficient to observe that all three assignment LOCs in B are dealing with the same object whose actype is C. It follows, therefore, that there can be no ClassCastException at (C)myB in the second sout despite the fact that B is wider than C, and since calls to toString() are all virtual (because the methods are non-static, non-private and non-final) , every time a printing stat fires, the toString() in C runs.

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